(x-3)^2/4=x-3

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Solution for (x-3)^2/4=x-3 equation: 



(x-3)^2/4=x-3

We move all terms to the left:

(x-3)^2/4-(x-3)=0

We get rid of parentheses

(x-3)^2/4-x+3=0

We multiply all the terms by the denominator


(x-3)^2-x*4+3*4=0

We add all the numbers together, and all the variables

(x-3)^2-x*4+12=0

Wy multiply elements

(x-3)^2-4x+12=0

We add all the numbers together, and all the variables

-4x+(x-3)^2+12=0

We move all terms containing x to the left, all other terms to the right

-4x+(x-3)^2=-12

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